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Why Does My Jquery Click Function Only Work Once?
This is a discussion on Why Does My Jquery Click Function Only Work Once?, within the Javascript section. This forum and the thread "Why Does My Jquery Click Function Only Work Once?" are both part of the Frameworks category.
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Jul 3 2008, 08:56 PM
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#1
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![]() Rapid Squeezer ![]() ![]() ![]() ![]() Posts: 146 Joined: 3-July 08 |
Here is the link to start the show
CODE <a onClick="showDebug(<? echo $rowbooked['uID']; ?>);">[?]</a> Here is the script to start the dancers CODE <script type="text/javascript"> function showDebug(uID) { $j.ajax({ type: "GET", url: "showBookingDebug.php", cache: false, data: "uID=" + uID, success: function(html){ $j("#showDebug" + uID).replaceWith(html); $j("#showDebug" + uID).show("fast"); } }); } $j(document).ready(function() { $j("#debugger").click(function() { $j(this).hide("slow"); }); }); </script> Here is the div where it happens CODE <div id="debugger"> <div style="display: none; margin-left: 75px; margin-top: 9px; width: 888px; clear: both;" id="showDebug<? echo $rowbooked['uID']; ?>"> </div> </div> Long play short, the idea is that the <div> #debugger pulls out some debugging information on the fly. Then on clicking it, it dissapears. That is OK. Works a treat. However, when I click on my fancy little question mark link again to do it all over, well, it just doesn't do anything. NOT ENTIRELY TRUE, as in the console of my firebug, it says that its retrieved the file, but it just doesn't display it on screen. Like it got locked down in hide(). Any ideas? This post has been edited by cosmicbdog: Jul 3 2008, 08:56 PM |
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Jul 3 2008, 10:25 PM
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#2
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![]() Squeeze Machine ![]() Posts: 766 Joined: 13-February 08 From: Catching the squeezed drips downunder. |
It would appear your problem lies here
CODE $j("#showDebug" + uID).replaceWith(html); You are placing the whole element with the text sent back from the ajax call and next time, there is *no* #showDebug element on the page to replace. Try using CODE $j("#showDebug" + uID).html(html); Which will replace the content of the element but not the element itself. -------------------- |
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Jul 4 2008, 12:29 AM
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#3
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![]() Rapid Squeezer ![]() ![]() ![]() ![]() Posts: 146 Joined: 3-July 08 |
Which will replace the content of the element but not the element itself. Doesn't that just make perfect sense now? Can you help me understand though how I have multiple divs with #debugger id and why the hide function I'm using only works for the first one? CODE $j(document).ready(function() { $j("#debugger").click(function() { $j(this).hide("slow"); }); }); My understanding is that this function would apply to anything that has id="debugger" and when clicked, would hide.... but it seems it only works for the first div that has this id on the page and not after. This post has been edited by cosmicbdog: Jul 4 2008, 12:30 AM |
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Jul 4 2008, 12:34 AM
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#4
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![]() Squeeze Machine ![]() Posts: 766 Joined: 13-February 08 From: Catching the squeezed drips downunder. |
Id's need to be unique on the page. They are ID's after all
If you want to do it for multiple divs do it on a per class basis. give all the divs you need a class of "debugger" and get them with CODE $j(".debugger").click(function () {$j(this).hide(); });
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Jul 4 2008, 01:50 AM
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#5
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![]() Rapid Squeezer ![]() ![]() ![]() ![]() Posts: 146 Joined: 3-July 08 |
Is that right... wow... that would make sense why most of the things I'm trying don't work.
Yep, this surely did the trick... my app is coming along so nicely. Thank you boss. |
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Jul 3 2008, 08:56 PM









